Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Can someone solve this question ~
[tex]\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}[/tex]
[tex]\boxed{\boxed{Step \: by \: step \: explanation \: required~}}\ [/tex]
​

Sagot :

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{x^2-9}{x^2+2x-3}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{(x+3)(x-3)}{x^2+3x-x-3}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{\cancel{(x+3)}(x-3)}{\cancel{(x+3)}(x-1)}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{x-3}{x-1}[/tex]

  • Apply limits

[tex]\\ \sf{:}\Rrightarrow \dfrac{-3-3}{-3-1}[/tex]

[tex]\\ \sf{:}\Rrightarrow \dfrac{-6}{-4}[/tex]

[tex]\\ \sf{:}\Rrightarrow \dfrac{3}{2}[/tex]

Hope you could understand.

If you have any query, feel free to ask.

View image Аноним
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.