Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Can someone solve this question ~
[tex]\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}[/tex]
[tex]\boxed{\boxed{Step \: by \: step \: explanation \: required~}}\ [/tex]
​

Sagot :

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{x^2-9}{x^2+2x-3}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{(x+3)(x-3)}{x^2+3x-x-3}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{\cancel{(x+3)}(x-3)}{\cancel{(x+3)}(x-1)}[/tex]

[tex]\\ \sf{:}\Rrightarrow {\displaystyle{\lim_{x\to -3}}}\dfrac{x-3}{x-1}[/tex]

  • Apply limits

[tex]\\ \sf{:}\Rrightarrow \dfrac{-3-3}{-3-1}[/tex]

[tex]\\ \sf{:}\Rrightarrow \dfrac{-6}{-4}[/tex]

[tex]\\ \sf{:}\Rrightarrow \dfrac{3}{2}[/tex]

Hope you could understand.

If you have any query, feel free to ask.

View image Аноним
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.