Answered

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work out m and c for the line: 5x-3y+4=0

Sagot :

charlief22

Answer:

[tex]m = \frac{5}{3}[/tex]  

[tex]b = \frac{4}{3}[/tex]

Step-by-step explanation:

The question requires you to rearrange the equation into the form:

y = mx + c

Which is the straight line equation, meaning rearrange for y:

Add 3y to both sides of the equation:

5x - 3y + 4 = 0

5x - 3y + 4 + 3y = 0 + 3y

5x + 4 = 3y

Divide both sides of the equation to isolate y:

[tex]\frac{5x}{3} + \frac{4}{3} = \frac{3y}{3}[/tex]

[tex]y = \frac{5}{3}x + \frac{4}{3}[/tex]

This means that  [tex]m = \frac{5}{3}[/tex]  and [tex]b = \frac{4}{3}[/tex].

Hope this helps!

Answer:

m = 5/3 and c = 4/3.

Step-by-step explanation:

5x - 3y + 4 = 0

-3y = -5x - 4

y = (-5/-3)x - 4/-3

y = 5/3 x + 4/3

y  = mx    +  c

So m = 5/3 and c = 4/3

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