150703
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

How many grams of N2 are required to react with 4.2 moles of Mg in the following process?

3 Mg + N2 → Mg3N2? (Mg = 24.3 g/mol, N = 14.0 g/mol)

Sagot :

Answer:

x = 0.45*28/3 = 4.2 g

Explanation:

showing work

N2 = 28 g/mole

3Mg + N2 → Mg3N2

3moles .. 28 g

0.45 moles .. x

x = 0.45*28/3 = 4.2 g (answer)