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YOU’RE GETTING A BRAINLIST IF YOU ANSWER THESE:

If you and I meet halfway between the fountain and the restrooms what are the coordinates of our meeting place?

If my cat and your dog meet halfway between the ball field and the swings what are the coordinates of their meeting place?

Now to the nearest yard how far are you and I to our pets after arriving to our meeting place?

YOURE GETTING A BRAINLIST IF YOU ANSWER THESE If You And I Meet Halfway Between The Fountain And The Restrooms What Are The Coordinates Of Our Meeting Place If class=

Sagot :

aklintworth

Answer:

Step-by-step explanation:

Question 1

Answer:   (1, -0.5)

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Explanation:

The x coordinates of the points for the restrooms and fountain are -2 and 4 in that order. Add up those values and divide by 2

(-2+4)/2 = 2/2 = 1

The midpoint of -2 and 4 on the number line is the value 1. So if the restrooms and fountain were on the x axis and at -2 and 4 respectively, then the midway point is 1 on that same number line. Note: The value 1 is exactly 3 units away from -2 and 4.

We'll use this idea for the y coordinates as well. Add them up, then divide by 2.

Add: 4+(-5) = -1

Divide by two:  -1/2 = -0.5

The y coordinate of the midpoint is -0.5

Overall, the midpoint between the restrooms and fountain is the point (1, -0.5)

For more info, check out the midpoint formula.

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Question 2

Answer:  (0, 0.5)

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Explanation:

We'll use the same idea as before. This time we focus on the locations of the swings and ball field only.

Add the x coordinates for each point: -5+5 = 0

Divide in half: 0/2 = 0

The x coordinate of the midpoint is 0

Repeat for the y coordinates.

Add: 5+(-4) = 1

Cut in half: 1/2 = 0.5

The y coordinate of the midpoint is 0.5

We get the midpoint (0, 0.5) which is where the two pets meet.

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Question 3

Answer: Approximately 1 yard

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Explanation:

Apply the distance formula for the results of the previous two questions.

So we'll apply the midpoint formula for the points (1, -0.5) and (0, 0.5)

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(1-0)^2+(-0.5-0.5)^2}\\\\d = \sqrt{(1)^2+(-1)^2}\\\\d = \sqrt{1+1}\\\\d = \sqrt{2}\\\\d \approx 1.414\\\\d \approx 1\\\\[/tex]

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