Answered

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13. Jay has 12 classic cars in his garage. He paid
$3,500 for each car 5 years ago. The cars are
currently worth $4,200 each. How much more
must the average value of the cars rise for the
combined value of these 12 cars to be exactly
$10,800 more than Jay paid for them?
A. $200.00
B. $700.00
C. $800.50
D. $ 841.67
E. $958.33
(May need worked out, please!?)

Sagot :

elsharony
Here I hope that this helps you out
View image elsharony
amyyyyyyyyyy

Answer:

I believe the answer would be A. $200.00

Step-by-step explanation:

This is because if jay has 12 cars that he paid 3,500$ each for, the total cost would have been $42,000.

And the current price is 4,200$ for each car.

If you add 200$ to each 4,200$ car, you get 4,400$

After, you take the amount for each car (4,400) and multiply it by 12 (the amount of cars purchased) and you get 52,800.

You then need to subtract the recent cost of 12 cars (52,800) by 42,000$ (the original cost for 12 cars) and you will get $10,800.

52,800-42,000=10,800

therefore, A.$200.00 would be the correct answer

I'm not sure if all calculations are correct, but I hope this helps! :)

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