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Sagot :
To find the distance between the homes of Tom and Jimmy, it is assumed
that the distances from their home to the café are equal.
- The distance between Tom and Jimmy's home is [tex]\underline{1,617.\overline 7 \ meters}[/tex]
Reasons:
The direction in which Tom and Jimmy walks = Towards each other
The speed at which Tom walks = 52 meters per minute
The speed with which Jimmy walks = 70 meters per minute
The time at which Tom leaves = 4 minutes earlier than Jimmy
The point at which they meet = The café
The rate of their speed = Constant
Required:
The distance between Tom and Jimmy home.
Solution:
Tom and Jimmy had a plan to walk at the same speed and meet up at the café.
We have;
The café is equal distance from Tom and Jimmy's houses.
Which gives the following simultaneous equation.
52 × (4 + t) = The distance of Tom's house from the café
70 × t = The distance of Jimmy's house from the café
- 52 × (4 + t) = 70 × t
52 × 4 = 70 × t - 52 × t = 18 × t
[tex]\displaystyle t = \frac{52 \times 4}{18} = \frac{104}{9} = 11.\overline{6}[/tex]
The time it take Jimmy to reach the café, t = [tex]\mathbf{11.\overline6}[/tex] minutes
The distance between their homes, d = 52 × (4 + t) + 70 × t
∴ d = 52 × (4 + [tex]11.\overline6[/tex]) + 70 × [tex]11.\overline6[/tex] = 1,617.[tex]\mathbf{\overline 7}[/tex]
- The distance between Tom and Jimmy's home = 1,617.[tex]\overline 7[/tex] meters
Learn more about simultaneous equations here:
https://brainly.com/question/12413726
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