katesamara
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

PLEASE HELP!!!! write the equation in slope-intercept form of the line that passes through (6,-11) and is perpendicular to the graph of y=-2/3x+12

Sagot :

amyyyyyyyyyy

Answer:

I believe the equation would be: y=3/2x-20

Step-by-step explanation:

This is true because, first you would need to find the slope from the equation, which is -2/3. But, for perpendicular, you would need to make it the exact opposite (which is this case would leave you with a slope of 3/2)

Ex: if you had -3/4, the slope for one that is perpendicular would be 4/3 (exact opposite)

After finding the slope, you take the points (6,-11) and plug it into the equation "y-y1=m(x-x1)"

y-y1=m(x-x1)

y+11=3/2(x-6)

-distribute the 3/2-

y+11=3/2x-18/2

y+11=3/2x-9

-subtract 11 on both sides-

y=3/2x-20

Im not sure if all calculations are correct, but I hope this helps! :)

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.