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Sagot :
Proof:-
In ∆TOP and ∆ZAP
[tex]\because\sf\begin{cases}\sf <O\cong <A(Given)\\ \sf TO\cong AZ(Given)\\ \sf <TPO\cong <ZPA(Opposite angles)\end{cases}[/tex]
Hence
∆TOP[tex]\cong[/tex]∆ZPA(Side-Angle-Side)
Step-by-step explanation:
Statement Reason
∠O ≅ ∠A Given
TO ≅ AZ Given
∠OPT and ∠ZPA are vertical angles Vertical angles theorem
∠OPT ≅ ∠ZPA Definition of vertical angles
ΔTOP ≅ ΔZAP Angle - angle -side AAS postulate
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