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find the inverse of f(x)=x^2-3x+2

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Sagot :

Answer:

Step-by-step explanation:

y = [tex]\frac{3}{2}[/tex] + [tex]\sqrt{x+\frac{1}{4} }[/tex] and y = [tex]\frac{3}{2}[/tex] - [tex]\sqrt{x+\frac{1}{4} }[/tex]

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Answer:

Step-by-step explanation:

f(x) = x² - 3x + 2

y = x² - 3x + 2

solve for x as a function of y

y - 2 = x² - 3x

complete the square by adding the square of half the x¹ coefficient to each side of the equation.

y - 2 + (-1.5)² = x² - 3x + (-1.5)²

      y + 0.25 = (x - 1.5)²

    [tex]\sqrt{y + 0.25}[/tex] = x - 1.5

                 x = 1.5 ± [tex]\sqrt{y + 0.25}[/tex]

now swap the x and y variables and revert to function notation

f(x) = 1.5 ± [tex]\sqrt{x + 0.25}[/tex]     domain is x ≥ -0.25

each input will have two outputs except where f(-0.25) = 1.5