Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Using the histogram, the mean of the data-set is estimated to be of 31.
- The mean, given an histogram, is the sum of the halfway points of each interval multiplied by it's relative frequency.
In this problem, the intervals and relative frequencies are:
- The first interval has halfway point 23 and relative frequency [tex]\frac{4}{30}[/tex].
- The second interval has halfway point 28 and relative frequency [tex]\frac{8}{30}[/tex].
- The third interval has halfway point 33 and relative frequency [tex]\frac{14}{30}[/tex].
- The fourth interval has halfway point 38 and relative frequency [tex]\frac{4}{30}[/tex].
Hence, the mean is:
[tex]E(X) = 23\frac{4}{30} + 28\frac{8}{30} + 33\frac{14}{30} + 38\frac{4}{30} = \frac{23(4) + 28(8) + 33(14) + 38(4)}{30} = 31[/tex]
For more on mean of histograms, you can check https://brainly.com/question/24651197
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.