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SalmonWorldTopper

Given info:- In ∆ABC, right-angled at c in which AB = 10in, BC = 26 in and we have to find out the measure of AC = ?

Explanation:

In right angled ∆OCB, AC ⟂ CB,

AB² = AC²+CB²

[By Pythagoras theorem]

(10)² = AC²+(26)²

10*10 = AC²+(26*26)

100 = AC²+676

AC² = 676-100

AC² = 576

AC = √(576)

AC = 24 in.

Hence, the measure of right-agled in which AC is 24 in.

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