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solve the system using substitution 5x+3y=-4 y-2x=6

Sagot :

m9882435

Solving steps:-

5x+3y=−4

y−2x=6

-->To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

5x+3y=−4,−2x+y=6

-->Choose one of the equations and solve it for x by isolating x on the left hand side of the equal sign.

5x+3y=−4

-->Subtract 3y from both sides of the equation.

5x=−3y−4

--> Divide both sides by 5.

x = 1/5(-3y - 4)

--> Multiply 1/5 −3y−4.

x = -3/5y - 4/5

--> Substitute -3y - 4/ 5 for x n the other equation, −2x+y=6.

-2 (-3/5y - 4/5) + y = 6

--> Multiply −2 times -3y - 4/ 5

6/5y + 8/5 + y = 6

--> Add 6y/5 to y

11/5y + 8/5 = 6

--> Subtract 8/5 from both sides of the equation.

11/5y = 22/5

--> Divide both sides of the equation by 11/5, which is the same as multiplying both sides by the reciprocal of the fraction.

y = 2

--> Substitute 2 for y in x= -3/5y - 4/5. Because the resulting equation contains only one variable, you can solve for x directly.

x = -3/5 x 2 - 4/5

--> Multiply -3/5 times 2.

x = -6 - 4/ 5

--> Add -4/5 to -6/5 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

x = -2

--> The equation is now solved.

Answer : x = -2, y = 2

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