jolen3a
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

solve the system using substitution 4x+3y=23 x-5=0

Sagot :

Answer:

y=1, x=5

Step-by-step explanation:

Since x-5=0 is given already, give the x a value and switch the 5 to the other side x-5=0 ----> x=5

Now we have a value for x, so plug x into the original equation,

4(5)+3y=23,

20+3y=23

Subtract both sides by 20

20-20+3y=23-20

3y=3

dvide both sides by 3

y=1

use the value for x we got earlier

y=1, x=5

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.