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How many grams are in 3.4 moles of Lead (IV) Sulfate (Pb(SO4)2)? ) Molar mass: 303.26 g/mol 131.0840​

Sagot :

shakilhussain2022

Answer:

1031.084g

Explanation:

n=m/M

m=n(M)

m = (3.4mol)(303.26g/mol)

1031.084g

Hope that helps

Answer:

1031.08

Explanation:

You start with 3.4 moles and you know that 6.022 x 10 ^ 23 = 1 mole( Avogadro's Number), so you just multiply those 2 numbers and the moles will cancel leaving you with grams of Lead Sulfate.

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