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Let f(x) = x2 − 16. Find f−1(x)

Sagot :

cinderofsoulsss

Answer:

[tex]f^{-1}(x)=\pm\sqrt{x+16}[/tex]

Step-by-step explanation:

[tex]f(x)=x^2-16[/tex]

To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.

[tex]y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}[/tex]

Now, you can swap the variables again and write the function.

[tex]f^{-1}(x)=\pm\sqrt{x+16}[/tex]

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