Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What are the solutions to the equation (x-1)(x+2)=-2?

Sagot :

Method used:-

Completing the square method.

Steps :-

[tex]( x - 1 ) ( x + 2 ) = - 2\\x^{2}+x-2=-2 \\x^{2}+x=-2+2 \\x^{2}+x=0[/tex]

Now, make the left hand side of the equation by adding the square of ½ to both sides of the equation.

[tex]x^{2}+x+\left(\frac{1}{2}\right)^{2}=\left(\frac{1}{2}\right)^{2} \\x^{2}+x+\frac{1}{4}=\frac{1}{4} \\\left(x+\frac{1}{2}\right)^{2}=\frac{1}{4} \\\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}} \\[/tex]

Simplify the equation. You'll get a +ve & -ve value.

[tex]x+\frac{1}{2}=\frac{1}{2} \\x+\frac{1}{2}=-\frac{1}{2}[/tex]

Simplify it further.

[tex]\boxed{\sf\:x=0}\\ \boxed{\sf\:x=-1 }[/tex]

The solutions are :-

x = 0 & x = -1

______

Hope it helps ⚜