Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Your teacher asks you to prepare 500 mL of a 2.75 molar solution of NaCl for an upcoming
laboratory experiment. Write a step-by-step procedure describing how you would carry out
this task.


Sagot :

To prepare 500 mL of a 2.75 molar solution of NaCl, measure 80.44 g of NaCl, place it in a 500 mL volumetric flask and fill it with water to the mark.

We'll begin by calculating the number of mole of NaCl in the solution

  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity = 2.75 M
  • Mole of NaCl =?

Mole = Molarity x Volume

Mole of NaCl = 2.75 × 0.5

Mole of NaCl = 1.375 mole

Next, we shall determine the mass of 1.375 mole of NaCl.

  • Mole of NaCl = 1.375 mole
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.375 × 58.5

Mass of NaCl = 80.44 g

Therefore, to prepare 500 mL of a 2.75 molar solution of NaCl, measure 80.44 g of NaCl, place it in a 500 mL volumetric flask and fill it with water to the mark.

Learn more about molarity: https://brainly.com/question/6685468