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A sled is launched off a cliff 39 m high and lands 74 m away from the base of the cliff. How fast was the sled launched?

Sagot :

The sled was launched with a velocity of 26.24 m/s

We'll begin by calculating the the time taken for the sled to land

Height (h) = 39 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]

  • Finally, we shall determine the velocity.

Time (t) = 2.82 s

Horizontal distance (s) = 74 m

Horizontal velocity (u) =?

[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]

Therefore, the sled was launched with a velocity of 26.24 m/s

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