Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Solve the inequality:
12+x≥3(x-6)​

Sagot :

Hello there! :)

The first step is to use the Distributive Property.

It states that

a(b+c)=ab+ac

Let's distribute 3, using this property:

3(x-6)=3x-18

Now, our inequality looks like so:

12+x≤3x-18

The next step is to move the variables to the left, using the opposite operation:

12+x-3x≤-18

12-2x≤-18

Now, move all the numbers to the right, using the opposite operation:

-2x≤-18-12

-2x≤-30

Divide both sides by -2 to isolate x.

Remember that when we divide by a negative variable, we change the inequality sign:

x≥15

Therefore, x≥15

Hope it helps.

~A lonely teen who helps others with a smile

-Grace :-)

Good luck.

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.