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Find the perimeter and area of this polygon.

Find The Perimeter And Area Of This Polygon class=

Sagot :

Answer:

perimeter=114

AREA= 308

Step-by-step explanation:

A^2 + B^2=C^2

then A+B=+C= P for triangle

52= triangle perimeter

rectangle:

(l+w)*2=p for rectangle=62

then add 52+62= 114

AREA- Triangle

b*h/2

22*10=220

220/2

= 110

AREA- Rectangle

l*w=A

22*9=198

ADD BOTH AREAS

198+110=308

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