Answer:
Approximately [tex]\text{$0.26$ radian}[/tex] every minute.
Step-by-step explanation:
Convert the unit of velocity (kilometers-per-hour) to meters-per-minute so as to match the unit of radius (meters) and angular velocity (per-minute.)
[tex]\begin{aligned}v &= 11\; \rm km \cdot h^{-1} \\ &= 11 \times \frac{1000\; \rm m}{1\; \rm km} \times \frac{1\; \rm h}{60\; \text{minute}} \\ &\approx 183.33\; {\rm m} \cdot\text{minute}^{-1}\end{aligned}[/tex].
Calculate the circumference of this circle:
[tex]\begin{aligned}c &= 2\,\pi\, r \\ &= 2 \, \pi \times 700\; \rm m \\ &\approx 4398.2\; \rm m\end{aligned}[/tex].
Find the time required (in minutes) for this vehicle to go around this circle:
[tex]\begin{aligned}\frac{4398.2\; \rm m}{183.33\; {\rm m} \cdot \text{minute}^{-1}} \approx 23.990\; \text{minute}\end{aligned}[/tex].
A full circle corresponds to an angle of [tex]2\, \pi \; \text{radian}[/tex] ([tex]360^{\circ}[/tex].) In other words, this vehicle would have turned [tex]2\, \pi \; \text{radian}\![/tex] in approximately [tex]23.990\; \text{minute}[/tex] if it travels at a constant speed. The rate at which this vehicle turn would be:
[tex]\begin{aligned}\frac{2\, \pi}{23.990\; \text{minute}} \approx 0.26\; \text{minute}^{-1}\end{aligned}[/tex].
In general, for angular velocity [tex]\omega[/tex], radius [tex]r[/tex], and velocity [tex]v[/tex], [tex]v = \omega\, r[/tex]. After updating the units, the angular velocity of this vehicle (the rate at which it turns) may also be found as:
[tex]\begin{aligned}\omega &= \frac{v}{r} \\ &\approx \frac{183.33\; \rm m \cdot \text{minute}^{-1}}{700\; \rm m} \\ &\approx 0.26\; \text{minute}^{-1}\end{aligned}[/tex].
