- Set of ordered pairs such that the range is one less than the domain is {-4, -3, -2, -1, 0, 1, 2}
- The equation 1 will be y = x - 1
- The equation 2 will be y = x + 2
Given the domain of values D = {-3, -2, -1, 0, 1, 2, 3}
1) If the set of range is one less than the domain, the required range will be:
Range = {-4, -3, -2, -1, 0, 1, 2}
2) If the set of range is 2 more than the domain, the required range will be:
Range = {-1, 0, 1, 2, 3, 4, 5}
The table of values is given as:
x y
-3 | -1
-2 | 0
-1 | 1
0 | 2
1 | 3
2 | 4
3 | 5
2) For equation 1, we will use the coordinate points (0. -1) and (1, 0)
The equation in slope-intercept form is given as y = mx + b
m = 0-(-1)/1-0
m = 1/1 = 1
Since the y-intercept is at (0, -1), hence b = -1
Substitute the given value into the formula:
Recall that y = mx + b
y = 1x + (-1)
y = x - 1
Hence the equation 1 will be y = x - 1
For equation 2, we will use the coordinate points (-1, 1) and (0, 2)
The equation in slope-intercept form is given as y = mx + b
m = 2-1/0-(-1)
m = 1/1 = 1
Since the y-intercept is at (0, 2), hence b = 2
Substitute the given value into the formula:
Recall that y = mx + b
y = 1x + 2
y = x + 2
Hence the equation 2 will be y = x + 2
4) The graph of each equation on a different coordinate plane is attached.
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