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Sagot :
Answer:
Step-by-step explanation:
That will be a square with a diagonal of 20
side length of 20sin45
and area of (20sin45)² = 200 units²
prove it you say?
Area of a rectangle is base times height
A = bh
With a radius of 10, the diagonals of any rectangle inscribed will be 20 units
20² = b² + h²
h = [tex]\sqrt{400 - b^2}[/tex]
A = bh
A = b[tex]\sqrt{400 - b^2}[/tex]
Area will be maximized when the derivative is set to zero
dA/db = [tex]\sqrt{400 - b^2}[/tex] - b²/ [tex]\sqrt{400 - b^2}[/tex]
0 = [tex]\sqrt{400 - b^2}[/tex] - b²/ [tex]\sqrt{400 - b^2}[/tex]
b²/[tex]\sqrt{400 - b^2}[/tex] = [tex]\sqrt{400 - b^2}[/tex]
b² = 400 - b²
2b² = 400
b² = 200
b = [tex]\sqrt{200}[/tex]
h = [tex]\sqrt{400 - b^2}[/tex]
h = [tex]\sqrt{400 - \sqrt{200}^2 }[/tex]
h = [tex]\sqrt{200}[/tex]
A = bh
A = [tex]\sqrt{200}[/tex]•[tex]\sqrt{200}[/tex]
A = 200 units²
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