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Sagot :
The equation of a line so that it is perpendicular to a given point will be
y-y0=[tex]\frac{-1}{m}[/tex] (x - xo)
The equation of a line so that it is perpendicular to a given point will be
y-y0=m (x - xo)
The standard equation of the line is better written in point-slope form expressed as:
y-y0=m(x - xo)
where: m is the slope of the given line (x0, y0) is any point of the giuven line.
m is the slope of the given line
(x0, y0) is any point on the given line
If the given slope of the line is m, the slope of the line perpendicular will be expressed as -1/m
The equation of a line so that it is perpendicular to a given point will be
y-y0=[tex]\frac{-1}{m}[/tex] (x - xo)
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