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Sagot :
The solutions to the equation [tex]3-k=\sqrt{3k+1}[/tex] are k = 1 and 8
The given equation is:
[tex]3-k=\sqrt{3k+1}[/tex]
Square both sides of the equation
[tex](3-k)^2=3k+1[/tex]
Expand the left side of the equation above
[tex](3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1[/tex]
Write the quadratic equation in standard form
[tex]k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\[/tex]
Factor the quadratic equation
[tex](k-8)(k-1)=0[/tex]
Use the zero product property
k - 8 = 0
k = 8
k - 1 = 0
k = 1
The solutions to the equation [tex]3-k=\sqrt{3k+1}[/tex] are k = 1 and 8
Learn more here: https://brainly.com/question/25840704
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