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How many atoms are in 80.45g of magnesium

Sagot :

Answer:

see below

Explanation:

1. 1 mol Mg = 24.31 g = 6.02 *10^23 atoms

     calculate the number of atomsin 80.45g Mg

         Numberof atoms = 6.02*10^23 Mg atoms / 24.31 g * 80.45 g

                                    = 1.99*10^24 atoms

2.1 mol C-12 = 12.01g = 6.02 * 10^23 atoms

    calculate the mass using

                                       = 12.01 g C / 6.02*10^23 atoms * 100 atoms

                                       = 1.99 * 10^-21 g

calsop85

Answer:

1.9926 * 10 ^24 

Explanation:

Molar Mass - Use Periodic table!

M ( Mg ) = 24.31 g / mole

n = 80.45 g : 24.31 g/mole = 3.31 moles

N a ( Avogadro`s constant ) = 6.02 * 10 ^23

N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^23

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