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What is the equation in vertex form of a parabola with vertex (2, 4) that opens downward and is stretched by a factor of 3?

Sagot :

Answer:

[tex]y=-\frac{1}{3}(x-2)^2+4[/tex]

Step-by-step explanation:

Vertex form of a parabola is [tex]y=a(x-h)^2+k[/tex] with the vertex being [tex](h,k)[/tex] and the vertical stretch or shrink factor as [tex]a[/tex].

Therefore, the correct equation is [tex]y=-\frac{1}{3}(x-2)^2+4[/tex]

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