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A triangle has a perimeter of 29 inches. Two of the other sides measure 9 inches and 9 inches. What is the length of the third side?

Sagot :

jcherry99

Answer:

Step-by-step explanation:

The perimeter = side1 + side2 + side3

P = 29

side1 = 9

side2 = 9

29 = 9 + 9 + side3

29 = 18 + side3           Subtract 18 from both sides

11 = side 3

lipor

Answer:

hb≈7.12in

a Side

9

in

c Side

9

in

P Perimeter

29

in

γ

c

a

h

b

b

h

b

h

b

c

γ

a

b

a

c

b

γ

P

c

γ

a

b

A

Using the formulas

A=hbb

2

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forhb

hb=﹣﹣P4+4P3a+4P3c﹣4(Pa)2﹣12P2ac﹣4(Pc)2+8Pa2c+8Pac2

2a﹣2P+2c=﹣﹣294+4·293·9+4·293·9﹣4·(29·9)2﹣12·292·9·9﹣4·(29·9)2+8·29·92·9+8·29·9·92

2·9﹣2·29+2·9≈7.1239in

Step-by-step explanation:

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