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Sagot :
The equation of the line is:
[tex]y=\frac{-1}{2}x-26[/tex]
The point-slope equation of a line is given as:
[tex]y-y_1=m(x-x_1)[/tex]
where m represents the slope, and is calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
For the line passing through the points (-32, - 10) and (-74, 11)
[tex]x_1=-32, y_1=-10, x_2=-74, y_2=11[/tex]
Substitute these points into the slope formula to get the slope of the line
[tex]m=\frac{11-(-10)}{-74-(-32)} \\\\m=\frac{11+10}{-74+32} \\\\m=\frac{21}{-42} \\\\m=\frac{-1}{2}[/tex]
Substitute [tex]m=\frac{-1}{2}, x_1=-32, y_1=-10[/tex] into the line equation
[tex]y-(-10)=\frac{-1}{2}(x-(-32))\\\\y+10=\frac{-1}{2}x-16\\\\y= \frac{-1}{2}x-16-10\\\\y=\frac{-1}{2}x-26[/tex]
The equation of the line is:
[tex]y=\frac{-1}{2}x-26[/tex]
Learn more on equation of a line here: https://brainly.com/question/13763238
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