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You have a Right Triangle with side lengths of 9ft and 12ft; solve for its perimeter and area.

Sagot :

Step-by-step explanation:

of course, we have to use Pythagoras.

c² = a² + b²

c is the Hypotenuse = the side opposite of the 90° angle.

and here is the problem : are 9 and 12 the legs. or is one of them the Hypotenuse ?

I don't know from the description.

let's see what we get one way or the other :

assumption : the known sides are the "legs".

c² = 9² + 12² = 81 + 144 = 225

c = 15 ft

that is a nice number. so, it looks like that was the intention.

just to be sure, here also the other options :

9² = 12² + side²

81 = 144 + side² that makes side² negative, so, not valid.

12² = 9² + side²

144 = 81 + side²

63 = side²

side = sqrt(63) this is not a nice round number, so, we go with the first option.

therefore, the 3 sides are

9 ft, 12 ft, 15 ft

perimeter = 9+12+15 = 36 ft

area = baseline×height/2

since this is a right-angled triangle, the "legs" with the enclosed 90° angle serve as baseline and height.

area = 9×12/2 = 9×6 = 54 ft²