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Sagot :
Step-by-step explanation:
We don't know if AB is a hypotenuse or leg.
If AB is hypotenuse:
- [tex]AB=\sqrt{AC^2+BC^2} =\sqrt{7^2+8^2} =\sqrt{49+64} =\sqrt{113}[/tex]
If AB is leg:
- [tex]AB=\sqrt{BC^2-AC^2} =\sqrt{8^2-7^2} =\sqrt{64-49} =\sqrt{15}[/tex]
For base/Perpendicular
- AB²=8²-7²
- AB²=64-49
- AB²=15
- AB=√15
For Hypotenuse
- AB²=8²+7²=64+49
- AB²=113
- AB=√113
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