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A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s

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onyebuchinnaji

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

  • applied force by the boxer, F = 1400 N
  • time of force action, t = 0.02 s

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

  • F is the applied force (N)
  • t is the time of force action (s)

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

Learn more about impulse here: https://brainly.com/question/25700778

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