zamanmutasim5
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Need help desperately

Need Help Desperately class=

Sagot :

burntsoggybread

Answer:

a) 4cd²

b) 3a²b³

Step-by-step explanation:

a) 8c⁴d⁵/2c³d³

1: you would divide the 8 by 2

2: subtract the exponents on c so it would be 4-3 = 1

3: subtract the exponents on d so it would br 5-3 = 2

4: put it all together so it would be 4c¹d² but you dont need the 1 above c

b) 1: divide 9 by 3

2: subtract exponents on a so it would be 3-1 = 2

3: subtract exponents on b so it would be 5-2 = 3

4: put it all together so it would be 3a²b³

hope this helped!! :)

         

                              Answer:

a.   4cd²       b.  3a²b³

Step-by-step explanation:

        [tex]\frac{8c^4d^5}{2c^3d^3}[/tex]

 =    [tex]\frac{8}{2} ( \frac{c^4}{c^3} )(\frac{d^5}{d^3})[/tex]  

  =     [tex]\frac{4}{1} (\frac{c}{1}) (\frac{d^2}{1} )[/tex]    Reduce number.  Substract exponent largest power

                           smallest power  

   =   4cd²  

b.    [tex]\frac{9a^3b^5}{3ab^2}[/tex]

        [tex]\frac{9}{3} (\frac{a^3}{a} ) (\frac{b^5}{b^2} )[/tex]

        [tex]\frac{3}{1} (\frac{a^2}{1}) (\frac{b^3}{1} )[/tex]       Reduce number.  Substract exponent largest power

                              smallest power  

    = 3a²b³

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.