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Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?

Sagot :

pstnonsonjoku

The speed with which Melinda’s car is bumped across the floor is 14 ms-1.

Total mass of the twins and the car = 300 Kg

Initial velocity of the twins car =  10 m/s

Total mass of Melinda and her car = 125 Kg

Initial velocity of Melinda's car = 0 m/s (at rest)

Final velocity of the twins car =  4.12 m/s

Final velocity of Melinda's car = ?

Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1

Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1

Using the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m1u1 + m2u2 = m2v1 + m2v2

(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)

3000 = 1236 + 125x

x =  3000 -  1236 /125

x = 14 ms-1

The speed with which Melinda’s car is bumped across the floor is 14 ms-1.

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