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From one point on the ground, the
angle of elevation of the peak of a
mountain is 10.38°, and from a
point 15,860 ft closer to the
mountain, the angle of elevation is
14.67º. Both points are due south of
the mountain. Find the height of the
mountain.
10.38°
一企一
14.67°
15,860 ft


Sagot :

Trigonometry allows to find the result for the question about the height of the mountain is:

  • The height mountain  is:  y = 9674.4 ft

Trigonometry allows finding relationships between the angles of a right triangle.

         [tex]tan \theta = \frac{y}{x}[/tex]  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = [tex]\frac{y}{x}[/tex]  

At the other point the angle is 10.38º.

        tan 10.38 = [tex]\frac{y}{x+15860}[/tex]

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

        x 1,429 = x + 15860

        x 0.429 = 15860

        x = [tex]\frac{15680}{0.429}[/tex]

        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

  • The height is y = 9674.4 ft

Learn more about trigonometry here: https://brainly.com/question/8120556

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