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The graph below shows the number of push-ups a
student completed in each of four 2-minute trials (A-
D) during a 15-minute exercise period.
70-1
65
60
Trial A
50
45
Trial B
Number of Push-ups
Trial
25
20
15
10
Trial D
5
0
D
2 3 4
6 7 8 9 10 11 12 13 14 15
Time in Minutes
The concentration of lactic acid in the student's
muscle tissue was most likely greatest during trial
A) A В) В
C) C D) D


Sagot :

Option D has the highest concentration of lactic acid in the student's muscle tissue.

We can arrive at this answer because:

  • Lactic acid increases its concentrations in the muscle due to a high physical effort in anaerobic conditions.
  • This promotes a lack of oxygenation in the muscle, which through contractions, causes the cell to partially catabolize glucose molecules.
  • The result of this is the creation of two pyruvic acid molecules, which will react with NADH2 molecules, creating lactic acid, which will build up in the muscle as the exercise continues.

As we can see in the information presented above, option D shows the performance of flexions with more intensity and for a longer period, which justifies a greater accumulation of lactic acid in the muscle.

It is important to remember that the accumulation of lactic acid in the muscle is a negative situation and that it can cause muscle pain and fatigue.

More information on lactic fermentation at the link:

https://brainly.com/question/13769502