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Given that T is the centroid of △DEF and FT=12

Given That T Is The Centroid Of DEF And FT12 class=

Sagot :

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

[tex]\mathbf{TQ : FT =1 : 2}[/tex]

Where FT = 12.

Substitute 12 for FT in the above ratio

[tex]\mathbf{TQ : 12 =1 : 2}[/tex]

Express as fraction

[tex]\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}[/tex]

Multiply both sides by 12

[tex]\mathbf{TQ =\frac{1 }{ 2} \times 12}[/tex]

This gives

[tex]\mathbf{TQ =\frac{1 2}{ 2}}[/tex]

Divide 12 by 2

[tex]\mathbf{TQ =6}[/tex]

The measure of FQ is calculated using:

[tex]\mathbf{FQ = FT + TQ}[/tex]

Substitute 12 for FT, and 6 for TQ

[tex]\mathbf{FQ = 12 + 6}[/tex]

Add 12 and 6

[tex]\mathbf{FQ = 18}[/tex]

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

https://brainly.com/question/11891965

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