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i just forgot this like ;-;

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Sagot :

Answer:

[tex] \boxed{\bf \dfrac{64}{729} }[/tex]

Hence,

[tex]\boxed{\bf \: \bigg( \dfrac{2}{3} \bigg) {}^ {6} = \dfrac{64}{729}} [/tex]

Step-by-step explanation:

Given arithmetic expression is :-

[tex]\sf \longmapsto(2/3) {}^{6} [/tex]

This expression may be rewritten as :-

[tex]\sf \longmapsto \bigg(\dfrac{2}{3} \bigg) {}^{6} [/tex]

6 is the index and 2/3 is the base.

In words, this may be represented as 2/3 raised to the Power 6.

Let's calculate.

It means that 2 is raised to the power of 6 and 3 is also raised to the power 6.

That is,

[tex]\sf \longmapsto \dfrac{ {2}^{6} }{ { 3}^{6} } [/tex]

It will be represented as,

[tex]\sf \longmapsto \: \dfrac{2 \times 2 \times 2 \times 2 \times 2 \times 2}{3 \times 3 \times 3 \times 3 \times 3 \times 3} [/tex]

On Simplification:-

[tex]\sf \longmapsto \dfrac{64}{729} [/tex]

In Decimal:-

[tex]\sf \longmapsto0.08(approx .)[/tex]

______________________________________

I hope this helps!

Please let me know if you have any questions.

~MisterBrian