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solve the following equation ​

Solve The Following Equation class=

Sagot :

Hi,

x² + 8x + 12 = 0

a= 1 ; b= 8 c= 12

∆ = b² - 4ac

∆ = 8² - 4*1*12

∆ = 64 - 4*12

∆ = 64 - 48

∆ = 16

∆>0 :

x1 = (-b-√∆)/2a = (-8-4)/2 = -12/2 = -6

x2 = (-b+√∆)/2a = (-8+4)/2 = -4/2 = -2

S= { -6 ; -2 }

x = -6

or x = -2

✅(•‿•)

Answer:

  • x = -6

  • x = -2

Step-by-step explanation:

x² + 8x + 12 = 0

➺ x² + 2x + 6x = 0

➺ x(x + 2) + 6(x + 2) =0

➺ (x + 6)(x + 2) = 0

Whether, x + 6 = 0

⠀⠀⠀⠀⠀➺ x = -6

⠀⠀or,⠀⠀⠀⠀ x + 2 = 0

⠀⠀⠀⠀⠀⠀➺ x = -2