Answer:
k=100, n=3, 1.5625, 10
Step-by-step explanation:
To find n and k, we can plug x and z in.
First we can try this for (1,100). We will get:
[tex]100=\frac{k}{1^{n} }[/tex]
Since 1 to any power is 1, we can assume that the denominator is 1 and therefore k=100.
Armed with k=100, we can plug numbers into the second equation.
[tex]12.5=\frac{100}{2^{n} }[/tex]
Moving [tex]{2^{n} }[/tex] to the left side, we get:
[tex]2^n=\frac{100}{12.5} }=8[/tex]
therefore we can solve and we see that n=3.
We can do the same for x=4, but since we have n, k, and x, we can plug these in to get z
[tex]z=\frac{100}{4^{3}} =1.5625[/tex]
We will do the same as previous but instead plug in x
[tex]\frac{1}{10}=\frac{100}{x^{3} }[/tex]
We isolate [tex]x^{3}[/tex] and get
[tex]x^{3} =1000[/tex]
Therefore x=10
