Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Ask your questions and receive precise answers from experienced professionals across different disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

f(x)=x^3+6x^2+x^1/2 and g(x)=x^1/2 Find f(x)/g(x)

A).x&5/2+6x&3/2-1
B).(x^5+6x^3+1)^1/2
C).x^5/2+6x^3/2+1
D).x^3/2+6x+x^1/4
E).x^3/2-6x+x^1/4

Sagot :

sqdancefan

Answer:

  C)  x^5/2 +6x^3/2 +1

Step-by-step explanation:

The relevant rule of exponents is ...

  a^b/a^c = a^(b-c)

__

  [tex]\dfrac{x^3+6x^2+x^{1/2}}{x^{1/2}}=x^{3-1/2}+6x^{2-1/2}+x^{1/2-1/2}=\boxed{x^{5/2}+6x^{3/2}+1}[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.