madisonsk07
Answered

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v = 128 – 32t
v is the velocity in ft/sec. It is NOT the height of
the ball.
t is the number of seconds after the ball is
thrown.
With what initial velocity is the ball thrown?
128 seconds
s
What is the y-intercept of the equation?
IS
[ Select]
What does the y-intercept mean?
t
[ Select ]
What is the x-intercept of the equation?
[ Select]
What does the x-intercept mean?
Select]
7
10
-
-
с
80°F

Sagot :

Answer: The Y intercept is 128 as well, which is the original velocity. Technically it should be v - intercept but whatever. The y  / v intercept is the original velocity. The X intercept should be the t intercept but again whatever. The x/t intercept is 4, meaning that the velocity is zero when t is 4

Step-by-step explanation: y/v intercept is when t = 0. v = 128 - 32(0) = 128

It is the initial velocity at t = 0. The X/t intercept is when v = 0. 0 = 128 - 32t, so 32t = 128, so t = 4. The x intercept means when the velocity is zero, which means that the ball is at its highest/farthest point.

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