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A group of 90 students plan to go camping over the weekend. At the last minute, some of the students decide not to go. The students who do go separated into four camps, where [tex]\frac{1}{7}[/tex] of the students stay at Hill Camp; [tex]\frac{1}{3}[/tex] of the students stay at Forest Camp; [tex]\frac{1}{4}[/tex] of the students stay at Field Camp; and the remaining students stay at Lake Camp. How many students were at Lake Camp?

Sagot :

Using fractions, it is found that of the students that went camping, [tex]\mathbf{\frac{23}{84}}[/tex] were at Lake Camp.

The students who went camping are divided according to the following fractions:

  • [tex]\frac{1}{7}[/tex] stayed at Hill Camp.
  • [tex]\frac{1}{3}[/tex] stayed at Forest Camp.
  • [tex]\frac{1}{4}[/tex] stayed at Field Camp.
  • The remaining x stayed at Lake Camp.

The sum of all these fractions is 100% = 1, hence:

[tex]\frac{1}{7} + \frac{1}{3} + \frac{1}{4} + x = 1[/tex]

[tex]\frac{12 + 28 + 21 + 84x}{84} = 1[/tex]

[tex]84x + 61 = 84[/tex]

[tex]84x = 23[/tex]

[tex]x = \frac{23}{84}[/tex]

Of the students that went camping, [tex]\mathbf{\frac{23}{84}}[/tex] were at Lake Camp.

A similar problem is given at https://brainly.com/question/24372153

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