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Sagot :
[tex]2.6\le2.6[/tex] classifies as [tex]\text{true}[/tex]
[tex]-6<-6[/tex] classifies as [tex]\text{false}[/tex],
[tex]3.1>-3.1[/tex] classifies as [tex]\text{true}[/tex]
so [tex]-5\ge -5[/tex] classifies as [tex]\text{true}[/tex]
To classify the statements, we need to evaluate each of them:
[tex]\text{Evaluate }2.6\le2.6\\\implies (2.6<2.6)\text{ or }(2.6=2.6)\\\implies \text{false or true}\\\implies\text{true}[/tex]
so [tex]2.6\le2.6[/tex] classifies as [tex]\text{true}[/tex], since the statement also allows [tex]2.6[/tex] to be equal to itself.
[tex]\text{Evaluate }-6<-6\\\implies\text{false}[/tex]
so [tex]-6<-6[/tex] classifies as [tex]\text{false}[/tex], since [tex]-6[/tex] is equal to itself, not smaller.
[tex]\text{Evaluate }3.1>-3.1\\\implies \text{true}[/tex]
so [tex]3.1>-3.1[/tex] classifies as [tex]\text{true}[/tex], since [tex]x>-x[/tex], for all real numbers
[tex]\text{Evaluate }-5\ge-5\\\implies (-5>-5)\text{ or }(-5=-5)\\\implies \text{false or true}\\\implies\text{true}[/tex]
so [tex]-5\ge -5[/tex] classifies as [tex]\text{true}[/tex], since the statement also allows [tex]-5[/tex] to be equal to itself.
Learn more about inequalities here: https://brainly.com/question/24786628
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