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List the angles of A KLM with vertices
K(-2,-2), L(2, 6), M(7, -2) in order
from smallest to largest.

Sagot :

abidemiokin

The required angles from smallest to largest are m<M < m<L < m<K

Given the coordinate of the triangle KLM given as K(-2,-2), L(2, 6), M(7, -2)

  • The angle opposite the side KL is m<M
  • The angle opposite the side KM is m<L
  • The angle opposite the side LM is m<K

Get the measure of KL, KM and LM using the distance formula as shown:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y)_1)^2}[/tex]

For the length KL with coordinate points K(-2,-2), L(2, 6)

[tex]KL=\sqrt{(2-(-2))^2+(6-(-2))^2}\\KL=\sqrt{4^2+8^2}\\KL=\sqrt{16+64}\\KL=\sqrt{80}\\KL =4\sqrt{5}[/tex]

For the length KM with coordinate points K(-2,-2), M(7, -2)

[tex]KM=\sqrt{(7-(-2))^2+(-2-(-2))^2}\\KM=\sqrt{9^2+0^2}\\KM=\sqrt{81}\\KM=9[/tex]

The length LM with coordinate points L(2,6), M(7, -2)

[tex]LM=\sqrt{(7--2)^2+(-2-6)^2}\\LM=\sqrt{5^2+(-8)^2}\\LM=\sqrt{25+64}\\LM=\sqrt{89}[/tex]

From the distances, we can see that side LM > KM > KL. Hence the required angles from smallest to largest are m<M < m<L < m<K

Learn more on distances between two points here: https://brainly.com/question/23848540

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