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Answer:

[tex]log_4(\frac{1}{64})=-3[/tex]

Step-by-step explanation:

[tex]log_b(b^x)=x[/tex]

  • Let b = base and x = the exponent

    Looking at the equation given, we know the base (the number with the exponent) is 4, the exponent itself is -3, and the value is 1/64. Based on this information, fill in the formula and simplify any values.

[tex]log_4(4^{-3})=-3\\log_4(\frac{1}{64})=-3[/tex]

Therefore, the logarithmic form is [tex]log_4(\frac{1}{64})=-3[/tex].

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