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Find the slope for (3,1)and (4,3)

Sagot :

y2-y1 / x2-x1

so, 3-1 =2 and 4-3=1
2/1 is 2
SenorMathWiz

Answer:

2

Step-by-step explanation:

slope formula : [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where the x and y values are derived from known points

We are given the points (3,1)and (4,3)

Given these points we can define our variables

(x1,y1) = (3,1) so x1 = 3 and y1 = 1

(x2,y2) = (4,3) so x2 = 4 and y2 = 3

Now that we have defined our variable, we plug them into the formula

Recall formula: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

x1 = 3 , y1 = 1 , x2 = 4 , y2 = 3

* plug in values *

[tex]\frac{3-1}{4-3}[/tex]

subtract 3 and 1 , and 4 and 3

[tex]\frac{3-1=2}{4-3=1} =\frac{2}{1} =2[/tex]

the slope is 2

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