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Sagot :
Using the z-distribution, it is found that the p-value is of 1.
At the null hypothesis, it is tested that the majority is not against the death penalty, that is:
[tex]H_0: p \neq 0.5[/tex]
At the alternative hypothesis, it is tested that the majority is against the death penalty, that is:
[tex]H_1: p > 0.5[/tex]
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
- [tex]\overline{p}[/tex] is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
In this problem, the parameters are: [tex]\overline{p} = 0.27, p = 0.5, n = 491[/tex].
Then, the value of the test statistic is:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.27 - 0.5}{\sqrt{\frac{0.5(0.5)}{491}}}[/tex]
[tex]z = -10.19[/tex]
Using a z-distribution calculator, for a right-tailed test, as we are testing if the proportion is greater than a value, the p-value is of 1.
A similar problem is given at https://brainly.com/question/16313918
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