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Sagot :
Answer:
c = -0.7
Step-by-step explanation:
It looks like you have the proportion ...
[tex]\dfrac{3.8}{4c+3}=\dfrac{2}{\left(\dfrac{2}{19}\right)}\\\\0.4=2(4c+3)\qquad\text{cross multiply}\\\\0.4=8c+6\qquad\text{eliminate parentheses}\\\\-5.6=8c\qquad\text{subtract 6}\\\\\boxed{c=-0.7}\qquad\text{divide by 8}[/tex]
Answer:
c = -0.7
Step-by-step explanation:
[tex]\rm⇢ \: \: \frac{3.8}{(4c + 3)} = \frac{2}{( \frac{2}{19} )} [/tex]
[tex]\rm⇢ \: \: 2(4c + 3) = 3.8( \frac{2}{19} )[/tex]
[tex]\rm⇢ \: \: 8c + 6 = 0.4[/tex]
[tex]\rm⇢ \: \: 8c = - 5.6[/tex]
[tex]\rm⇢ \: \: c = - 0.7[/tex]
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