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Sagot :
Answer:
(b) {-8, 2}
Step-by-step explanation:
The given equation
x³ +6x -16 = 0
cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.
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Perhaps you want to factor ...
x² +6x -16 = 0
(x +8)(x -2) = 0
This has solutions x = -8 and x = 2 that make the factors be zero.
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Additional comment
"Cubed" refers to an exponent of 3.
Answer:
Option b] (2,-8)
Step-by-step explanation:
⇒ x³ + 6x - 16 = 0
♦ the value of one root is irrational and other two are complex roots.
⇒ x² + 6x - 16 = 0
⇒ (x + 8)(x - 2) = 0
⇒ x = 2 , -8
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